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	<title>Comments on: Not Science Fiction</title>
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	<link>http://asymptotia.com/2008/01/22/not-science-fiction/</link>
	<description></description>
	<pubDate>Wed, 07 Jan 2009 18:53:33 +0000</pubDate>
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		<title>By: Lab Lemming</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-109675</link>
		<dc:creator>Lab Lemming</dc:creator>
		<pubDate>Sun, 17 Feb 2008 01:13:30 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-109675</guid>
		<description>So was this formulated before or after positrons were discovered?
'cause, what the science fiction antimatter promoters never seem to remember is that bananas produce antimatter from e+ decay of 40K. 
Of course, since the electron capture and b- decays are much more common, your average banana only cranks out one positron every 2 hours.  If you want one to appear during a 50 minute university lecture, you should probably bring a whole hand to class.</description>
		<content:encoded><![CDATA[<p>So was this formulated before or after positrons were discovered?<br />
&#8217;cause, what the science fiction antimatter promoters never seem to remember is that bananas produce antimatter from e+ decay of 40K.<br />
Of course, since the electron capture and b- decays are much more common, your average banana only cranks out one positron every 2 hours.  If you want one to appear during a 50 minute university lecture, you should probably bring a whole hand to class.</p>
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		<title>By: theresa f</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-107441</link>
		<dc:creator>theresa f</dc:creator>
		<pubDate>Sat, 02 Feb 2008 23:50:07 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-107441</guid>
		<description>wow, that's intense. haha i'm going to have to take a break, then come back and read it again :) ...looking forward to hearing the BBC anti-matter conversation!</description>
		<content:encoded><![CDATA[<p>wow, that&#8217;s intense. haha i&#8217;m going to have to take a break, then come back and read it again <img src='http://asymptotia.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> &#8230;looking forward to hearing the BBC anti-matter conversation!</p>
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		<title>By: Aaron F.</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106299</link>
		<dc:creator>Aaron F.</dc:creator>
		<pubDate>Fri, 25 Jan 2008 01:49:01 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106299</guid>
		<description>Oh, cool! Thanks, EJ! And, uh, I'm pretty sure Ambitwister's comment wasn't there when I posted my second one... :P</description>
		<content:encoded><![CDATA[<p>Oh, cool! Thanks, EJ! And, uh, I&#8217;m pretty sure Ambitwister&#8217;s comment wasn&#8217;t there when I posted my second one&#8230; <img src='http://asymptotia.com/wp-includes/images/smilies/icon_razz.gif' alt=':P' class='wp-smiley' /></p>
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		<title>By: EJ</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106087</link>
		<dc:creator>EJ</dc:creator>
		<pubDate>Tue, 22 Jan 2008 19:33:07 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106087</guid>
		<description>The way it's written now is for a "free" particle. Just replace the zero on the right-hand side with E*psi, or for arbitrary potential V(x) use (E - V(x))*psi.</description>
		<content:encoded><![CDATA[<p>The way it&#8217;s written now is for a &#8220;free&#8221; particle. Just replace the zero on the right-hand side with E*psi, or for arbitrary potential V(x) use (E - V(x))*psi.</p>
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		<title>By: Aaron F.</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106035</link>
		<dc:creator>Aaron F.</dc:creator>
		<pubDate>Tue, 22 Jan 2008 15:45:49 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106035</guid>
		<description>But wait... I don't see anything that looks like a potential! Where does the potential term go if you want to solve for, say, an electron in a box?</description>
		<content:encoded><![CDATA[<p>But wait&#8230; I don&#8217;t see anything that looks like a potential! Where does the potential term go if you want to solve for, say, an electron in a box?</p>
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		<title>By: Aaron F.</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106033</link>
		<dc:creator>Aaron F.</dc:creator>
		<pubDate>Tue, 22 Jan 2008 15:39:13 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106033</guid>
		<description>Ohhh... now I see that the gamma^mu are actually the Dirac matrices in disguise. Tricky tricky!</description>
		<content:encoded><![CDATA[<p>Ohhh&#8230; now I see that the gamma^mu are actually the Dirac matrices in disguise. Tricky tricky!</p>
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		<title>By: Ambitwistor</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106032</link>
		<dc:creator>Ambitwistor</dc:creator>
		<pubDate>Tue, 22 Jan 2008 15:37:39 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106032</guid>
		<description>Aaron:  no, the gamma^mu aren't relativistic dilation factors, they're &lt;a href="http://en.wikipedia.org/wiki/Dirac_matrices" rel="nofollow"&gt;Dirac matrices&lt;/a&gt;.</description>
		<content:encoded><![CDATA[<p>Aaron:  no, the gamma^mu aren&#8217;t relativistic dilation factors, they&#8217;re <a href="http://en.wikipedia.org/wiki/Dirac_matrices" rel="nofollow">Dirac matrices</a>.</p>
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		<title>By: Aaron F.</title>
		<link>http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106031</link>
		<dc:creator>Aaron F.</dc:creator>
		<pubDate>Tue, 22 Jan 2008 15:35:14 +0000</pubDate>
		<guid isPermaLink="false">http://asymptotia.com/2008/01/22/not-science-fiction/#comment-106031</guid>
		<description>&lt;i&gt;That's&lt;/i&gt; the Dirac equation? I thought it was supposed to be complicated! Am I to understand that gamma^mu = 1/sqrt(c^2 - v_mu^2), as usual?</description>
		<content:encoded><![CDATA[<p><i>That&#8217;s</i> the Dirac equation? I thought it was supposed to be complicated! Am I to understand that gamma^mu = 1/sqrt(c^2 - v_mu^2), as usual?</p>
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